Question

If g(x) = 6 + x + e^x, find g^-1of (7).

Answer 1

try x=0 see if \[g(0)=7\] then you will have your answer

Answer 2

you really have to guess this one. no computing it using algebra

Answer 3

ln(x-6)/2 gives me 0/2 or zero is this right

Answer 4

Plug g(x)=7, and solve for x.

Answer 5

that is not the inverse. you would have to solve \[x=6+y+e^y\] for y. good luck!

Answer 6

yes but for this one you have to guess. you check that \[g(0)=6+0+e^0=6+1=7\]
so \[g^{-1}(7)=0\]

Answer 7

don't try to find \[g^{-1}(x)\] using algebra

Answer 8

hello anwar. seen quite a spate of wrong answers here tonight

Answer 9

not from you of course

Answer 10

Yeah, Plugging \(7\) for g(x) gives: \(x+e^x=1\), then \(x=0\) is the only solution. Hence \(g^{-1}(7)=0\).

Answer 11

thanks

Answer 12

exactly but you solved the last one by inspection yes?

Answer 13

Yes! But, it's not hard to see it. It can be easily solved by graphing as well.

Answer 14

And hello satellite :)