Question

what is the square root of x^4 + 7?

Answer 1

Hoot! You just asked your first question! Hang tight while I find people to answer it for you. You can thank people who give you good answers by clicking the 'Good Answer' button on the right!

Answer 2

okay so 4+7 is 11 and the square root of 11 is? what are 2 of the same #s that divide into 11?like the square root of 36 is 6 bcuz 6 times 6 is 36.

Answer 3

(x^4 + 7)^1/2

Answer 4

\[\sqrt{x ^{4}+7}\] or\[\sqrt{x ^{4+7}}\]??

Answer 5

na I need a specific answer

Answer 6

it is apparently factorable

Answer 7

There is no good way to simplify that problem. It is simply \[\sqrt(x^4+7)\]

Owlfred, your reply was useless.
Helpneededlady, 11 is prime, and that was not this persons question anyway.

Jman, is there more to the problem?

Answer 8

no

Answer 9

thats it I have to simplify it further

Answer 10

Find f(√x + 2) if f(x) = x4 + 5

Answer 11

that is the problem

Answer 12

only it is x to the fourth

Answer 13

Well then you already gave us the solution to your problem, and it cannot be simplified further.

Answer 14

no it has to be simplified

Answer 15

I did notice some calculation errors, that could be your problem.

The answer ends up being \[(\sqrt(x+2))^4+5\]. At this point you can simplify and get a different answer.

Answer 16

f(√x + 2) if f(x) = x4 + 5
(√x + 2)^4 + 5
= (x+2)^2 +5
= x^2 + 2x +9

Answer 17

i dont think we r allowed to do that suzi

Answer 18

why?
f(√x + 2) means x = √x + 2
then plug into equation

Answer 19

suzi, (sqrtx + 2)^4 is not (x + 2)^2

Answer 20

Guyc is correct, my bad I didn't notice the calculation errors, but her general procedure was correct.

Answer 21

√x + 2 = (x+2)^1/2
(√x + 2)^4 = ((x+2)^1/2)^4
(x+2)^ 1/2 * 4
(x+2)^2

Answer 22

it was wrong

Answer 23

ok up to u, that was my answer and thank you.

Answer 24

The difficulty we're having is calculating (sqrt x + 2) ^4. Multiplying by hand by brute force I get:

x^2 + 8x^(3/2) + 24x + 32x^(1/2) + 16

which is horrible