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OpenStudy (angela210793):
\[\sqrt{\log_{2}3*\log_{3}4*\log_{1/3}5 }\]
OpenStudy (anonymous):
yes, its a complex no.
OpenStudy (angela210793):
it'd b a negative no. under sqr right?
OpenStudy (anonymous):
yes
OpenStudy (angela210793):
thnx :)
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OpenStudy (anonymous):
ask more problems :)
OpenStudy (angela210793):
i have abt 300....want to see them all? :)
OpenStudy (anonymous):
yeps :D
OpenStudy (angela210793):
ok :)
OpenStudy (angela210793):
\[9^{2-\log_{3}5 }\]
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OpenStudy (anonymous):
value=81/25
OpenStudy (anonymous):
i hope that's what u want!
OpenStudy (angela210793):
\[9^{2}/9^{\log_{3}5 } this is how u did \it?\]
OpenStudy (angela210793):
this is how u did it****
OpenStudy (anonymous):
the denominator=\[3^{(2\log_{3}5)}= 3^{\log_{3}25}=25\]
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OpenStudy (anonymous):
I hope u know the properties of logarithms.
OpenStudy (angela210793):
yea i do....
OpenStudy (anonymous):
ask if u have any problems :)
OpenStudy (angela210793):
let me google translate smth plssss :)
OpenStudy (angela210793):
w8 i lost whr it was...
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OpenStudy (anonymous):
any problem?
OpenStudy (angela210793):
found it :)
OpenStudy (angela210793):
sea water contains 3% salinity.how much water should we throw out in 1liter....so that the percentage will b 2%
OpenStudy (angela210793):
So so so sorry 4 my english :S:S :$
OpenStudy (angela210793):
Did u get what i am looking 4?
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OpenStudy (anonymous):
is the answer 200/3 L.?
OpenStudy (angela210793):
idk.......
OpenStudy (anonymous):
Your question: Sea water has 3% salinity. How much volume of water (in litres) should be expelled to get 2% salinity?
Is this ur question?
Was my ans right?
OpenStudy (angela210793):
yea this was the q..but i don't know how to solve it.....idk if ur answer is right...:(
OpenStudy (anonymous):
ok, my logic goes:
In 100 L water there is 3 vol salt.
Therefore 1 vol salt is in 100/3 L water
So 2 vol salt is in 200/3 L water.
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OpenStudy (angela210793):
maybe...thnx :):)
OpenStudy (angela210793):
another 1??
OpenStudy (anonymous):
any other question? 299 to go :)
OpenStudy (angela210793):
hahah lool.there are only abt 1/3 i can't solve :P:P:P
OpenStudy (angela210793):
\[\log_{2}15!=\log_{2}16!=? \]
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OpenStudy (anonymous):
False equality
OpenStudy (angela210793):
yea...there may be typing errors.....let me give another 1
OpenStudy (angela210793):
f(x)=ax^2+bx+c
f(2)=f(-3)=0 find a/b=?
OpenStudy (angela210793):
I'm going to get smth 2 drink...want anything(since ur helping me?) :P
OpenStudy (anonymous):
may be u can give me a glass of milkshake?
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OpenStudy (angela210793):
sure :P :)
OpenStudy (anonymous):
-b/a=-1. therefore a/b=1
OpenStudy (anonymous):
observe -3+2=-b/a
OpenStudy (angela210793):
O.o some explanation pls?
OpenStudy (anonymous):
sum of the roots=-b/a. Hope u know this.
BTW is my glass of milkshake ready..coz in my part of the world its abt 50C
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OpenStudy (anonymous):
any problems?
OpenStudy (angela210793):
yea i know tht....OMG!!!! why don't i use wht i know ? :(:(:(:(:(
ur milkshake is ready...(whr do u live? Sahara? )
OpenStudy (angela210793):
thnx by the way :)
OpenStudy (anonymous):
any more?
OpenStudy (angela210793):
i got a lot more problems here but they are with conics and graphics...:(:(:( i don't think u can help me...:(....but let me see :)
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