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Mathematics 17 Online
OpenStudy (anonymous):

Find f'(x) when f(x)=x^2+x , using the definition of the derivative, if that makes sense..

OpenStudy (owlfred):

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OpenStudy (angela210793):

F'(x)= 2x+1

OpenStudy (angela210793):

(x^n)'=X^(n-1)...u know this?

OpenStudy (anonymous):

Kinda :/

OpenStudy (anonymous):

x^n=nx^(n-1)

OpenStudy (angela210793):

yea i 4got tht...sorry ur right

OpenStudy (anonymous):

no problem...

OpenStudy (angela210793):

^_^

OpenStudy (anonymous):

it says to use the definition, so i think you are supposed to write \[lim_{h->0}\frac{f(x+h)-f(x)}{h}=lim_{h->0}\frac{(x+h)^2+(x+h)-(x^2+x)}{h}\]

OpenStudy (anonymous):

if you just need the answer then angela gave it to you but if you have to write it to hand in you need to use the definition, not the power rule.

OpenStudy (anonymous):

\[\frac{x^2+2xh+h^2+x+h-x^2-x}{h}=\frac{2xh+h+h^2}{h}=2x+1+h\]and now let h to to zero to get your answer.

OpenStudy (anonymous):

Thanks! :)

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