Question

Write the equation of a line in slope-intercept form that is perpendicular to y=-5/6x+2 and passes through (12, -4).

Answer 1

ah! i hate perpendicular!!!
and does the perpindicular lines has to be = to -1 if yes i can help

Answer 2

^^ aroub idk, i think so!

Answer 3

almost aroub - if the slope of a line is m then the slope of perpendicular = -1/m

Answer 4

ya it has to be = to -1

Answer 5

so its y=-1 ??

Answer 6

idk i really forgot the perpendicular

Answer 7

no the slope of the perpendicular linr wiil be -1/(-5/6) which simplifies to 6/5

Answer 8

ya i think your right because if u simplified it it will be = -1

Answer 9

so its y=-1x+-5/6 ?

Answer 10

no the 5/6 is the coefficient of x i.e. (6/5)x
the equation u want is y = (6/5)x + 2

Answer 11

your AWSOME (: (: thanks alot (:

Answer 12

the general form of the slope-intercept equation is y = mx +c where m = slope of the line and c is the intercept on the y-axis

Answer 13

no probs bailey

Answer 14

thanks (: can you help with one last problem like this?

Answer 15

yes ok

Answer 16

Write the equation of a line in slope-intercept form that is perpendicular to 3x+2y=6 and passes through the point (3, 0).

Answer 17

thanks (:

Answer 18

first manipulate the equation to get it in y=mx+c form
divide by 2 (because we have 2x):

3x/2 + y = 3
y = -(3/2)x + 3
-so we can see that the slope = -(3/2)
and the intercept on the y axis 3. slope of perpndclr. = -1/-(3/2) = 2/3
so our equation is

y = (2/3)x + 3

Answer 19

sorry on line 2 I should have put 2y not 2x

Answer 20

to get rid of the fraction we can multiply each term of the equation b 3

3y = 2x + 9

this is equivalent to the fractional equation

Answer 21

thankss (:

Answer 22

the questions are a bit strange though - you do not need the coordinates of the point to work out the problem

Answer 23

okay (:

Answer 24

if you have a similar problem which gives you the equation and a point on the line you use another form of the formula

i e y - y1 = m(x - x1)
where m = slope of the line and (x1,y1) are the coordinates of the given point

Answer 25

yes this is the easiest way to do it i agree:)