(2x^3+3x^2-19x-1) / (x-4)
do you know how to use synthetic division?
i was gonna ask that! *pouts*
2 3 -19 -1 4 8 44 100 ________________________________ 2 11 25 99
yes but its scketchy
list the coefficients, which is the top line 2 3 -19 -1
then since you are dividing by \[x-4\] put a 4 on the side
bring down the 2 to the bottom line. 2 3 -19 -1 4 _____________________________ 2
\[2\times 4 =8\] 2 3 -19 -1 4 8 ___________________________ 2
\[8+3=11\] 2 3 -19 -1 4 8 ___________________________ 2 11
\[4\times 11 = 44\] 2 3 -19 -1 4 8 44 ___________________________ 2 11
\[-19+44=25\] 2 3 -19 -1 4 8 44 ___________________________ 2 11 25
\[4\times 25=100\] 2 3 -19 -1 4 8 44 100 ___________________________ 2 11 25
\[-1+100=99\] 2 3 -19 -1 4 8 44 100 ___________________________ 2 11 25 99
you have divided a polynomial of degree 3 by a polynomial of degree 1 so your answer is a polynomial of degree 2 thus \[2x^2+11x+25+\frac{99}{x-4}\]
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