Question

@amistre64 will u help me in smth pls?

Answer 1

depends on what I have to do with smth :)

Answer 2

O.o..let me attach the problem pls...

Answer 3

U have to find the area of the circle...

Answer 4

it is a rhomb ***

Answer 5

i could see this as looking for the radius; which would indicate the a triangle in Q1

Answer 6

its a 3-4-5 right triangle

Answer 7

we then find the max area of a square that fits in it...maybe; or the max part of the circle to fit it

Answer 8

w8..i think i got how to solve it....all we have to do is find the height at ODC triangle and that=r :)

Answer 9

And then S=pi*r^2

Answer 10

Right?

Answer 11

this was what u were talking abt 2? Thnx a loot :)

Answer 12

the equation of the line that we want is:

(0,3) ; (4,0) ; the slope then being 3/4 or....

y = -(3/4)x + 3 right? that is the equation for the hyp ... that line of 5

Answer 13

we want a perp line to this that goes thru the origin (0,0) if anything

Answer 14

y = (4/3)x

Answer 15

the distance R is the distance from the origin to the point where these 2 lines meet right?

Answer 16

ehe...

Answer 17

r=12/5?

Answer 18

(4/3)x = (3/4)x +3

dunno yet still figuring this out the hard way lol

Answer 19

I think it should be
-(3/4)x=(4/3)x+4
Amistre...

Answer 20

w8 is easy...S(odc)= B*H/2=3*4/2=6
S(odc) is also=OE*DC/2=6----> OE=12/DC=12/5

Answer 21

the slope of the hyp I drew is -3/4 with a y int at (0,3) right?

Answer 22

I didn't get ur way......:(:(:( why with coordinates? O.o :(

Answer 23

my way is sound to me; i understand graphs and lines better than drawings

Answer 24

Your solution is nice angela :)

Answer 25

Wht abt my way? is it wrong?

Answer 26

Oh thnx :) :)

Answer 27

4 up and 3 over is the same region as 3 up and 4 over, ...

Answer 28

i dont really know if your way is right or wrong yet ;)

Answer 29

hmmmm.....

Answer 30

Her solution based on computing the area of ODC in two ways.
First: 1/2*3*4
Second* 1/2*CD*r = 1/2*5*r

Answer 31

Ehe...

Answer 32

(4/3)x = (-3/4)x + 3 [3]

4x = (-9/4)x +9 [4]

16x = -9x + 36

25x = 36

x = 36/25 did I get that right?

Answer 33

I didn't get ur way so i can't tell it if it is right or not....
Thank u very much anyway :):):):)

Answer 34

Amistre, the y-intercept is at (0,4)

Answer 35

4 36
-- * --- = y
3 25


4 12
-- * --- = y = 48/25
1 25

R = sqrt(x^2 + y^2)

R = sqrt((36/25)^2+(48/25)^2)

Answer 36

watch; it can be; but im actually using the other side; even tho I inadvertantly flipped it; it doesnt matter if we have 4 over and 3; or 3 over and 4 up; its the same triangle just flipped on itself with the same amount of circle it it ...

Answer 37

its the point of tangency that is important; in my figuring

Answer 38

let me read it from the start once again...

Answer 39

like this

Answer 40

Yes, your computation gives the same r :)

Answer 41

thank u both :)

Answer 42

R = 12/5 yay!! lol

Answer 43

:D ^_^

Answer 44

so that verifies your answer angela :) I know my way is solid, which is why I went that route

Answer 45

Will u see another 1 with inflexion points? (Is this how u call it?)

Answer 46

inflection points are where the graph stays along a course in a general direction.. sure

Answer 47

^_^ ok w8 :)

Answer 48

f(x)=x^4+c*x^3+x^2 what should b X so it will have 2 inflect. points? and then 1?

Answer 49

'X' or 'c' ?

Answer 50

f'= 4x^3 +3cx^2 +2x

f'' = 12x^2 +6cx +2 = 0 for inflection points

Answer 51

it says x...

Answer 52

x, as far as I can tell, is an input and has no real effect on the graph of this thing; the constants describe the path it takes

Answer 53

how are they defining inflection?

Answer 54

they who? O.o

Answer 55

they as in the people who designed the question, the authors of the material that you are using .... those guys

Answer 56

I see the answers; but the question should be what value should 'c' be...

Answer 57

C'mon...idk the words in english...............:S

Answer 58

ok u solve it 4 c...

Answer 59

f'' = 12x^2 +6cx +2 = 0 in order for this to have 2 real roots; we have to manipulate the discriminate of the quadratic formula....

Answer 60

36c^2 -4(2)(12) > 0 for 2 inflections

36c^2 -4(2)(12) = 0 for 1 inflection

Answer 61

36c^2 -96 = 0

36c^2 = 96

c^2 = 96/36

c = +- sqrt(96)/6 for one inflection

Answer 62

and greater than that for 2 inflections

Answer 63

http://www.wolframalpha.com/input/?i=sqrt%2896%2F36%29

Answer 64

whr did tht 36c^2 come from?O.o Florida? :P

Answer 65

it comes from taking the 1st and 2nd derivatives of the given equation

Answer 66

youd have to understand a little calculus to get the idea of it; but basically I used proven methods to find when the 2nd derivative = 0

Answer 67

y = x^4+c*x^3+x^2

y' = 4x^3 +3cx^2 +2x

y'' = 12x^2 +6cx +2 ; when y'' = 0 we have a point of inflection

Answer 68

y'' is a quadratic that can have its roots figured out by the quadratic formula; the discriminant of the quad formula tells us how many roots we will have

Answer 69

b^2 -4ac

(6c)^2 - 4(2)(12)

36c^2 -96 has to be greater than 0 for it to have 2 points for inflection

36c^2 -96 has to equal 0 for it to only have 1 point of inflection

Answer 70

so you solve the equations of the discriminate for c..

Answer 71

if we know what c is ro get the discriminate to = 0; then we should assume that larger values of c will make it greater then 0 for 2 roots

Answer 72

ahaaa.....i got it....Thnx ^_^

Answer 73

Will u help me in smth else?..... if u don't mind ofc...

Answer 74

i gotta finish my international business homework; its due today..

Answer 75

Oh..Ok..I'm sorry...didn't know tht....
Thnx a lot 4 helping me and good luck with ur hw :)

Answer 76

thnx :) and good luck with yours :)

Answer 77

^_^