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how do you simplify ln square root e, and is the answer e^2?
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no it is \[\frac{1}{2}\]
\[ln(x)=y\] same as \[e^y=x\] \[ln(\sqrt{e})=ln(e^{\frac{1}{2}})\]
this is starting to make a lot more sense thanx a lot!
and since clearly \[e^{y}=e^{\frac{1}{2}}\] makes \[y=\frac{1}{2}\] we get \[ln(e^{\frac{1}{2}})=\frac{1}{2}\]
this of it this way. \[ln(x)\] is the power you raise e to to get x. therefore \[ln(e^y)=y\]
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just like \[log_3(3^2)=2\]
and \[log_{10}(.001)=-3\] since \[10^{-3}=.001\]
10 ^-4 = 0.0001?
yes, since \[10^{-4}=\frac{1}{10^4}=\frac{1}{10000}=.0001\]
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