the area of a triange can be modeled: A(x)=x^3-1. The length is x-1. Find a polynomial to represent the width of the triangle. (the answer is x^2 + x +1 .... how do u get that?)

Question

the area of a triange can be modeled:  A(x)=x^3-1. The length is x-1. Find a polynomial to represent the width of the triangle. (the answer is x^2 + x +1 .... how do u get that?)

anonymous · Answer

Is this an equilateral triangle? or an arbitrary triangle?

watchmath · Answer

Notice that 
$x^3-1=(x-1)(x^2+x+1)$
So the width od the triangel is $2(x^2+x+1)$

anonymous · Answer

not sure why the "2" is there.  
$$\frac{x^3-1}{x-1}=x^2+x+1$$

watchmath · Answer

I guess area of triangle is 1/2*base*height

anonymous · Answer

is the length and width?
can we base and sides?

anonymous · Answer

oops you are right.  how could i doubt it?

anonymous · Answer

OMG I MENT RECTANGLE SRY GUYS

anonymous · Answer

lol well i read "rectangle' too so it must have been a subliminal message.  then there is no 2!

anonymous · Answer

x^3−1
--------
x−1               =x^2+x+1

how is that equal to that?

anonymous · Answer

actually, you are just going to use the formula of the area of a rectangle which is length times width
A=lw
$$x ^{3}-1=w(x-1)$$
divide both sides by x-1
then you will get x^3−1 
                      -------- 
                         x−1 
which is equal to x^2+x+1 through factoring its gcf.