Question

e^-(x^2+y^2) -> re^-r^2

x^2 + y^2 = r^2

where did r in front of e^-r^2 come from?

Answer 1

you change this inside of the integral right?

Answer 2

yeah it's for double integral using polar

Answer 3

the r is coming form the fact that dy dx = rdr dtheta

Answer 4

yeah hes right