Question

Need help. Problem says to rationalize and simplify
6 sq rt2 divided by square root 2-3

Answer 1

I am coming up with -12-18 square root 6 divided by 7

Answer 2

\[\frac{6\sqrt{2}}{\sqrt{2}-3}=\frac{6\sqrt{2}\times (\sqrt{2}+3)}{(\sqrt{2}-3)\times (\sqrt{2}+3)}=\frac{12+18\sqrt{2}}{-7}\]

Answer 3

Don't you need to get rid of the -7?

Answer 4

no.

Answer 5

why need to? -7 is a rational number.
(Why do we rationalize? Because to make the denominator a rational number)

Answer 6

understood bastax?

Answer 7

The example in the book shows getting rid of the -7 by multiplying by -1

Answer 8

Would my answer be correct if that was the case?

Answer 9

sometimes authors try to bring the negative sign upwards. But keeping -7 or 7 in denominator is just the same. The answer is rationalized as long as the denominator is a rational.

Answer 10

your answer is correct.

Answer 11

u can bring the negative sign on the top by multiplying up and down with -1, if ur tutor taught u so.

Answer 12

Awesome. Thank you!