Question

looking to integrate a differential equation on both sides... d^2C/dz^2 = -zA* dC/dz
how would I go about doing this?

Answer 1

Hoot! You just asked your first question! Hang tight while I find people to answer it for you. You can thank people who give you good answers by clicking the 'Good Answer' button on the right!

Answer 2

thanks! i'll be sure to give credit where credit is due. just to let you know, I simplified the constants in the equation into "A"

Answer 3

you replied to an automated message that really does nothing but post that you have aquestion in the chatroom box :)

Answer 4

there you are :)

Answer 5

thanks I noticed that when i clicked around. need an answer though!

Answer 6

d^2C/dz^2 = -zA* dC/dz hmm....

havent done to many of these so I dont know alot of the techniques, except for swapping variables when doing a first derivative..

Answer 7

its a secondary order differential equation.

Answer 8

C'' = -zA C' ...

Answer 9

Id say divide both sides by C'... but thats just a guess :)

Answer 10

its outta my league.... good luck with it :)

Answer 11

d^2C/dz^2 = -zA* dC/dz

(D^2+Az)C=0
where D=d/dz

Answer 12

http://www.wolframalpha.com/input/?i=dC%28dC%2Fdz%29%2Fdz+%3D+-zA+%28dC%2Fdz%29

Answer 13

thanks anyway. its for transport phenomenon in biological systems :P

Answer 14

solution says that form is in a form of a natural exponential. can anyone explain?

Answer 15

i tried to recall the solution of higher order DE, but could not,away from it for a long time,i just remember the formation of auxilliary eq