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OpenStudy (anonymous):
use a calculator and count it manualy.
OpenStudy (anonymous):
i think it's around >1000
OpenStudy (anonymous):
i mean <1000
OpenStudy (anonymous):
(60^2 + 60 )/2
OpenStudy (anonymous):
oops
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OpenStudy (anonymous):
i am wrong
OpenStudy (anonymous):
all "even" would be (60^2 + 60) /4 ???
OpenStudy (anonymous):
There are 30 even integers between 1 and 60.
The first and last pair add to 62.
So there are 15 pairs of integers who's sum is 62.
Therefore the total is 62 * 15 = 930
OpenStudy (nowhereman):
No, you are approaching this wrong.
Even between 1 and 60 are 2, 4, 6, ..., 60 so 2*(1, 2, 3, ..., 30) thus you get the sum 2*30*31/2 = 30*31 = 930
OpenStudy (anonymous):
^ you are right, thanks for correction
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OpenStudy (anonymous):
this is an arithmetic sequence of the following form a = 2n from n = 1 to n = 30.
now use the formula for the arithmetic series: sum = (n/2) * (last term + first term)
so sum = (30/2) * (2+30) = 480