3px (p + x + 2px)
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If you aren't solving for x, and simply distributing, 3p^2x + 3px^2 + 6p^2x^2
lucasmedina10 is correct! Can you break it down to show me how you did it? Thanks
polpak come back to my question
Just multiply the 3px by each of the terms in the sum: \[3px (p + x + 2px)\] \[=3px(p) + 3px(x) + 3px (2px)\] \[=3p^2x + 3px^2 + (3\cdot 2)p^2x^2\] \[=3p^2x + 3px^2 +6p^2x^2\]
oh sorry it was just an expression and need siplification
So, looking at (p + x + 2px) you can see there are three "parts" to the expression. 3px (p + x + 2px) is asking you to multiply each part by 3px and fitting it into a simplified expression. So first multiply 3px by p. Then multiply 3px by x, and lastly multiply 3px by 2px. 1. When you multiply 3px by p, you get 3p^2x 2. When you multiply 3px by x, you get 3px^2 3. When you multiply 3px by 2px, you get 6p^2x^2 Now put it all together by adding them! Since they are all positive, you can easily use plus signs. That is how you get the answer 3p^2x + 3px^2 + 6p^2x^2.
thanks
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