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Mathematics 15 Online
OpenStudy (anonymous):

3px (p + x + 2px)

OpenStudy (owlfred):

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OpenStudy (anonymous):

If you aren't solving for x, and simply distributing, 3p^2x + 3px^2 + 6p^2x^2

OpenStudy (anonymous):

lucasmedina10 is correct! Can you break it down to show me how you did it? Thanks

OpenStudy (anonymous):

polpak come back to my question

OpenStudy (anonymous):

Just multiply the 3px by each of the terms in the sum: \[3px (p + x + 2px)\] \[=3px(p) + 3px(x) + 3px (2px)\] \[=3p^2x + 3px^2 + (3\cdot 2)p^2x^2\] \[=3p^2x + 3px^2 +6p^2x^2\]

OpenStudy (anonymous):

oh sorry it was just an expression and need siplification

OpenStudy (anonymous):

So, looking at (p + x + 2px) you can see there are three "parts" to the expression. 3px (p + x + 2px) is asking you to multiply each part by 3px and fitting it into a simplified expression. So first multiply 3px by p. Then multiply 3px by x, and lastly multiply 3px by 2px. 1. When you multiply 3px by p, you get 3p^2x 2. When you multiply 3px by x, you get 3px^2 3. When you multiply 3px by 2px, you get 6p^2x^2 Now put it all together by adding them! Since they are all positive, you can easily use plus signs. That is how you get the answer 3p^2x + 3px^2 + 6p^2x^2.

OpenStudy (anonymous):

thanks

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