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Find the derivative of the function f(x) = (t^5-3t^3+2t^2e1)/2t^2
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You can use http://www.wolframalpha.com/input/?i=derivative+of+%28t^5-3t^3%2B2t^2e1%29%2F2t^2
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I'm not understandint their answer i didnt get it like that i divided everything by 2t^2
(f/g)' = (f'*g - f*g')/g^2
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huh?
and its suppose to be h(t) sorry i dont know if that makes a difference
and its suppose to be h(t) sorry i dont know if that makes a difference
This is the rule what you must use
we're suppose to use the power rule we didnt learn the quotient rule yet
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Then hmm wait a moment
3/2 t^2 -3/2te^1
thats what i got but i'm not sure about the e (natural number)
(f ° g)' = (f' ° g) g' and this rule you know?
nope
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