Question

When a 140g piece of metal at 70 degrees C is
placed in 220g of water at 0 degrees C, the metal
is cooled, and the water is warmed and
both come to a final temperature of 10=C.
What is the specific heat of the metal?

?

Answer 1

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Answer 2

The heat exchanged between the metal and the water is the same (assuming that this is a closed system (which it isn't by the way)). Therefore:
\[C _{water}*m _{water}*\Delta T_{water} = C_{metal}*m_{metal}*\Delta T_{metal}\]
\[C_{metal} = C_{water}m_{water}\Delta T_{water}/(m_{metal}\Delta T_{metal}) = 1.16 KJ/kgK\]
for example sand has similar specific heat.