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Mathematics 7 Online
OpenStudy (anonymous):

in a 30-60-90 triangle the shortest side ha a length of one what are the other two measurments?

OpenStudy (anonymous):

its an impossible problem,

OpenStudy (anonymous):

how?

OpenStudy (anonymous):

60,90

OpenStudy (anonymous):

the other two sides have a variable

OpenStudy (anonymous):

and its length not degrees

OpenStudy (anonymous):

the other two sides are sqrt(3) and 2 for the hypotenuse. shortest side is opposite the 30 degree angle.

OpenStudy (anonymous):

thanks.. can you help me again?

OpenStudy (anonymous):

sure

OpenStudy (anonymous):

its the same kind of problem but the side is 8

OpenStudy (anonymous):

ok all 30-60-90 triangles are similar. so if the ratio of the sides is always 1:sqrt(3):2 and if the side corresponding to 1 is 8 we get 8, 8sqrt(3), 16

OpenStudy (anonymous):

do you know about similar triangles?

OpenStudy (anonymous):

not at all.. but the answer i got was 4, sqrt(3) and it was right

OpenStudy (anonymous):

not if the smallest side of the triangle was 8. which side was 8?

OpenStudy (anonymous):

if the hypotenuse was 8 then you would get 4, 4sqrt(3), 8

OpenStudy (anonymous):

if the shortest side is = h, then by using Law of Sines: sin30/h = sin60/x where is x= longer side (another one; across from 60 degree angle); now: \[x=h*sqrt{\3\}\] now use Pythagorean Theorem to find c... let me know if there is a problem :)

OpenStudy (anonymous):

oh man that was the problem m sorry my mistake

OpenStudy (anonymous):

c=2h

OpenStudy (anonymous):

was the shortest side 1 for the first problem you asked or was that hypotenuse also?

OpenStudy (anonymous):

no the question i last asked had the hypotenuse of eight.. the first one was correct.

OpenStudy (anonymous):

allright sounds good.

OpenStudy (anonymous):

thanks

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