Question

really confusing, please help!
a committee will consist of 3 teachers/3 students chosen from the 24 teachers & 145 students available. half of the teachers and 99 students are women.
find the probability that the committee has only female members?

Answer 1

(12C3/24C3)+(99C3/145C3)

Answer 2

why plus?

Answer 3

sorry i think that will be *

Answer 4

so (12C2)(99C3)/((24C3)*(145C3))

Answer 5

here two conditions have to be satisfied simultaneously *. 12C3 not 12C2

Answer 6

smoochum, i got 115 for the solution for that other problem about multiples of 3

Answer 7

:O from the work we did??

Answer 8

@ dipankarstudy i think your first answer (12C3/24C3)+(99C3/145C3) is right , it's + not *

Answer 9

can you explain why is a + and not *

Answer 10

because the committee consists of 3 teachers OR 3 students
it can't consist of both students and teachers
it can only consist of 3 teachers, or it consists only of 3 students
you use * if the committee consists of 3 teachers AND 3 students

Answer 11

oh it says 3 teachers and 3 students

Answer 12

both the teachers and students so *

Answer 13

no, it says 3 teachers/3 students ,
doesnt that mean 3 students OR 3 teachers?

Answer 14

how would you do
only 1 teacher and only 1 student who are women then?
adding?

Answer 15

oh i just simplified it dindatc XD sorry for the confusion

Answer 16

(12C3/24C3)+(99C3/145C3)

12C3 means 3 females are picked from 12 female teachers
99C3 means 3 females are picked from 99 female students

Answer 17

how about 1 teacher and 1 student?

Answer 18

my attempt for that one is: 12C1*12C2/24C3 * 99C1*46C2/145C3

Answer 19

Ways of choosing only females = (12C3 x 99C3) = 34 506 780

the ways of picking 3 teachers and 3 students with no restriction = (24C3) x (145C3)

Answer 20

answer to first question = [34 506 780 ] /[ 24C3 x 145C3 ] = 0.03426....