How do the areas compare when the dimensions of one are 3 times the dimension of the other?

Question

owlfred · Answer

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anonymous · Answer

if you have a one by one square the area is 1.  if you have a 3 by 3 square the area is 9.  so it varies with the square of the side

anonymous · Answer

if your square is x by x then area is $$x^2$$
if your square is 3x by 3x then area is $$(3x)^2=9x^2$$

anonymous · Answer

so second is 9 times the first.

anonymous · Answer

but one square is 15 cm and 1 is 135 cm

anonymous · Answer

if one square is 15 cm i assume you mean the side is 15cm yes?

anonymous · Answer

no the area

anonymous · Answer

oh the area is 15 square cm  so the side is $$\sqrt{15}$$

anonymous · Answer

but the question is  How do the areas compare when the dimensions of one are 3 times the dimension of the other?

anonymous · Answer

as i said, if one has side x and the other 3x the area of the second is 9 times the area of the first .  just like 135 is 9 times 15

anonymous · Answer

so the answer is, 
"if the dimensions of one square are 3 times the dimensions of the other, then the area of the bigger square is 9 times the area of the smaller."

anonymous · Answer

thankss <3

anonymous · Answer

Wait sorry. The question was:  How do the areas of two parallelograms compare when the dimensions of one are 3 times the dimension of the other?