solve for x 8-11x=5+4/3(2-x) 4/3 is a fraction read 4 3rds
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OpenStudy (owlfred):
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OpenStudy (anonymous):
when solving this, x becomes a decimal point not a whole number. is that what you are asked for?
OpenStudy (anonymous):
i just need to solve for x i know it will be a fraction, decimal, or whatever. This problem is driving me nuts!
OpenStudy (anonymous):
i got \[x=\frac{-1}{37}\]
OpenStudy (anonymous):
steps??
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OpenStudy (anonymous):
Is the equation this?
\[8-11x=5+\frac{4}{3}(2-x) \]
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
The first thing I would do is multiply both sides by 3 to get rid of the fraction.
OpenStudy (anonymous):
thats where im stuck what exactly do I multiply by 3?
OpenStudy (anonymous):
Everything.
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\[8-11x=5+\frac{4}{3}(2-x)\] distribute \[\frac{4}{3}\]
so it equals to \[8-11x=5+\frac{8}{3}-\frac{4}{3}x\]
in one step i added \[(5+\frac{4}{3}) \] and -11x from left to right
we get the following
\[8=\frac{23}{3}-\frac{37}{3}x\]
\[subtract \frac{23}{3} \to both sides\]
\[\frac{1}{3}=-\frac{37}{3}x\]
then divide.
OpenStudy (anonymous):
That works too, but lots of fractions that way.
OpenStudy (anonymous):
polpak, i solved it this way. I like fractions.
OpenStudy (anonymous):
ok...
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OpenStudy (anonymous):
Yo dawg. I herd you liek fractions so I put some fractions in your fractions so you can divide when you divide.
OpenStudy (anonymous):
;)
OpenStudy (anonymous):
:)
OpenStudy (anonymous):
Jwaddell, do you like fractions?
OpenStudy (anonymous):
i hate them they cause issues like this
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OpenStudy (anonymous):
Jwaddell no matter what way you solve it. The answer is the same. if you want to. polpak or my self could help you solve by getting rid of fractions first.
OpenStudy (anonymous):
Ok, well if you multiply both sides of the equation you will rid yourself of the fraction.
OpenStudy (anonymous):
everyway ive tried comes out different
OpenStudy (anonymous):
multiply by 3.
OpenStudy (anonymous):
\[3[8−11x]=3[5+{4\over 3}(2−x)]\]
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OpenStudy (anonymous):
So distribute the 3 on the left and you get:
24 - 33x = 15 + 4(2-x)
OpenStudy (anonymous):
got that
OpenStudy (anonymous):
Ok, so now distribute the 4 on the right hand side
OpenStudy (anonymous):
What have you got?
OpenStudy (anonymous):
24-33x=15+8-4x
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OpenStudy (anonymous):
Perfect. Now combine the 15 + 8
OpenStudy (anonymous):
k
OpenStudy (anonymous):
23
OpenStudy (anonymous):
Ok so you have
\[24 - 33x = 23 - 4x\]
So lets add 33x to both sides.
OpenStudy (anonymous):
yes
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OpenStudy (anonymous):
24=23-37x???
OpenStudy (anonymous):
Nope.. -4x + 33x = ?
OpenStudy (anonymous):
or is it -4+33 to = 29x
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
k
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OpenStudy (anonymous):
So we have 24 = 23 + 29x
Now we subtract 23 from both sides.
OpenStudy (anonymous):
so then 1=29x
OpenStudy (anonymous):
Right!
OpenStudy (anonymous):
1/29=x
OpenStudy (anonymous):
Yep
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OpenStudy (anonymous):
Perhaps beehive should not like fractions so much ;p
OpenStudy (anonymous):
i guess so. I hurry a lot too much.
OpenStudy (anonymous):
thank you!!!!
OpenStudy (anonymous):
very welcome. Be sure to review what we did so you can understand how to do it again in the future.