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Mathematics 22 Online
OpenStudy (anonymous):

Evaluate the following limit: lim x -> 1 sin (x-1)/ (x^2 + x -2) i got 1/3

OpenStudy (anonymous):

Did you use l'Hopital?

OpenStudy (anonymous):

we didnt learn it yet so we cant use it

OpenStudy (anonymous):

I think you have to. You have 0 over 0 here.

myininaya (myininaya):

sin(x-1)/(x-1)(x+2) sin(x-1)/(x-1)->1 as x->1 so now we have 1/(x+2)->1/3 since x->1

OpenStudy (anonymous):

this is what i did lim x-> 1 sin (x-1)/(x-1)(x+2) sin (x-1)/x-1 x 1/x+2 then substitute the lim in 1x 1/3 1/3

myininaya (myininaya):

remember sinx/x->1 as x->0 so sin(x-1)/(x-1)->1 as x->1

OpenStudy (anonymous):

sin(x-1)/(x-1)->1 as x->1 using l'Hopital?

OpenStudy (anonymous):

oh yay myiniaya! we did the same thing

myininaya (myininaya):

no using sinx/x->1 as x->0

OpenStudy (anonymous):

yes, but how do you evaluate that limit without l'hopital?

myininaya (myininaya):

we could use the squeeze theorem to show sinx/x->1 as x->0

OpenStudy (anonymous):

I mean someone could tell you, but they would have had to do it. Or I guess squeeze theorem. But either way I'd like to see more of a justification there.

myininaya (myininaya):

i could totally prove this sinx/x thing give me a sec and i will post

OpenStudy (anonymous):

the lim is x-> 1 though

OpenStudy (anonymous):

I know it is.

OpenStudy (anonymous):

I just don't know that you know it is ;p

myininaya (myininaya):

what

OpenStudy (anonymous):

lol so i cant use the squeeze theorem

OpenStudy (anonymous):

what? You have to use squeeze theorem.

myininaya (myininaya):

lol what polpak what are you saying to me

myininaya (myininaya):

do you guys want me to prove it or not?

OpenStudy (anonymous):

no. I'm good. I was just saying that purp should give some justification when he uses it in his argument

myininaya (myininaya):

ok

OpenStudy (anonymous):

then isnt my answer right

OpenStudy (anonymous):

it is right.

myininaya (myininaya):

yes it is i think polpak just wants you to understand why sinx/x->1 as x->0

OpenStudy (anonymous):

i am a girl thank you very much

OpenStudy (anonymous):

so whats the problem?

OpenStudy (anonymous):

'he' is not gender specific.

myininaya (myininaya):

im a girl too. what do you mean you are a girl? are you saying we can't do math as well as guys?

OpenStudy (anonymous):

she means I said 'he' before and she was correcting my use of that pronoun

myininaya (myininaya):

oh lol sorry

OpenStudy (anonymous):

but 'he' is correct usage when you don't know the person's gender.

myininaya (myininaya):

no i don't believe you polpak

OpenStudy (anonymous):

why? exactly is that because my teacher did this long proof on the board

OpenStudy (anonymous):

it's true! she is gender specific. he is not.

myininaya (myininaya):

don't make me growl i do not want to be referred to as a he

OpenStudy (anonymous):

but purple is girly anyway were here for the math lol

OpenStudy (anonymous):

Well now that I know you are a woman I will refer to you as she if it makes you feel better =)

OpenStudy (anonymous):

http://en.wikipedia.org/wiki/Gender-neutral_pronoun

myininaya (myininaya):

no im here to defend my sex

myininaya (myininaya):

lol

OpenStudy (anonymous):

no i mean why is sinx/x = 1

OpenStudy (anonymous):

no i mean why is sinx/x = 1

myininaya (myininaya):

i will make you a proof k

OpenStudy (anonymous):

because it is. You can prove that it is using the sqeeze theorem or l'hopitals.

OpenStudy (anonymous):

this website is freezing please dont type fast we'll confuse ourselves

OpenStudy (anonymous):

It gets laggy when the question gets too long.

OpenStudy (anonymous):

ok thank you gents {i assume} will you help me with my other questions

OpenStudy (anonymous):

Of course.

myininaya (myininaya):

myininaya (myininaya):

i made you a pretty proof its posted in the attachment

OpenStudy (anonymous):

i'll post it somewhere else to cut the lag

OpenStudy (anonymous):

aww :$ thank you

myininaya (myininaya):

does it make sense alittle?

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