Question

Which equation is the perpendicular bisector of the line segment with endpoints (-2, 4) and (6, 8)

Answer 1

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Answer 2

first you need the slope of this line which is
\[m=\frac{8-4}{6-(-2)}=\frac{4}{8}=\frac{1}{2}\]

Answer 3

since
\[m=\frac{1}{2}\] this means the perpendicular line has slope
\[m=-2\] the negative reciprocal now we need to find a point on that line

Answer 4

the midpoint between (-2,4) and (6,8) is
\[(\frac{-2+6}{2},\frac{4+8}{2})=(2,6)\]

Answer 5

use point slope formula to get
\[y-6=-2(x-2)\]
\[y-6=-2x+4\]
\[y=-2x+10\]