∫ (e^x)lnx dx =?
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use integration by parts
Laplace20, are u sure u can get the answer by using integration by parts?????
im never sure about anything. why dont you try it
Integration by parts impossible to solve it. 100% impossible!!!
u = ln x , dv = e^x , du = 1/x , v = e^x = ln x * e^x - integral e^x *1/x
nevermind, this cant be integrated
this is not an elementary function
algebraic, log, inverse trig, trig, exponential,
what is this a trick question?
no, this can be done using integration by parts , just you need to apply it twice
its like how you integrate e^x sin(x) or e^(x)cos(x)
contining from above, ie I (integral we want ) = ln x * e^x - integral e^x *1/x
let u=e^x , dv = (1/x) dx
so du= e^x dx , and v= ln(x)
SO I = e^x ln(x) - [ e^(x) ln(x) - integral ( e^x ln(x) dx ) ]
but that integral e^x lnx is what we started with, it was "I" so I = I huh , thats a bit strange that method didnt work :|
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