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Mathematics 7 Online
OpenStudy (anonymous):

∫ (e^x)lnx dx =?

OpenStudy (owlfred):

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OpenStudy (anonymous):

use integration by parts

OpenStudy (anonymous):

Laplace20, are u sure u can get the answer by using integration by parts?????

OpenStudy (anonymous):

im never sure about anything. why dont you try it

OpenStudy (anonymous):

Integration by parts impossible to solve it. 100% impossible!!!

OpenStudy (anonymous):

u = ln x , dv = e^x , du = 1/x , v = e^x = ln x * e^x - integral e^x *1/x

OpenStudy (anonymous):

nevermind, this cant be integrated

OpenStudy (anonymous):

this is not an elementary function

OpenStudy (anonymous):

algebraic, log, inverse trig, trig, exponential,

OpenStudy (anonymous):

what is this a trick question?

OpenStudy (anonymous):

no, this can be done using integration by parts , just you need to apply it twice

OpenStudy (anonymous):

its like how you integrate e^x sin(x) or e^(x)cos(x)

OpenStudy (anonymous):

contining from above, ie I (integral we want ) = ln x * e^x - integral e^x *1/x

OpenStudy (anonymous):

let u=e^x , dv = (1/x) dx

OpenStudy (anonymous):

so du= e^x dx , and v= ln(x)

OpenStudy (anonymous):

SO I = e^x ln(x) - [ e^(x) ln(x) - integral ( e^x ln(x) dx ) ]

OpenStudy (anonymous):

but that integral e^x lnx is what we started with, it was "I" so I = I huh , thats a bit strange that method didnt work :|

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