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Question: use the fact that y=e^3x is an obvious of each of the following equation to find a second and the general solution. a: y''-6y''+9=0 b: xy''-3(x+1)y'+9y=0
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y''-6y'+9=0 auxiliary eq. : \[\lambda ^{2} -6\lambda +9=0\] has one root: 3 so the general solution in this case is (A+Bx)e
\[(A+Bx)e ^{3x}\]
for the B part ask someone else, I am not sure
for b: e^3x . e^ln-3 im not sure and i need help about b
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