these are hard to put on here but what is the solution to the system of equations
|{ -3x-3y+2z=-7

Question

these are hard to put on here but what is the solution to the system of equations
   |{  -3x-3y+2z=-7
<|{               z=1
   |{    -2x-3y+z=-6

anonymous · Answer

first plug z = 1 into equns. 1 and 3 to give 2 equns. in x and y which u can solve by elimination

anonymous · Answer

-3x -3y +2 = -7
-2x -3y +1 = -6

subtractng the above eqautions :
-x +1 = -1
x = 2
Plug x=2 in second equn:
-2(2) -3y + 1 = -6
-3y = -6 -1 +4 = -3

y = 1

Solution is x=2, y=1 and z =1

anonymous · Answer

$$-3x-4y+2=-7$$
$$-2x-3y+1=-6$$
first is $$-3x-4y=-9$$ second is 
$$-2x-3y=-7$$
first is 
$$3x+4y=9$$
second is 
$$-2x-3y=-7$$
multiply first by 2 and second by 3
$$6x+8y=18$$
$$-6x-9y=-21$$
 add tp get 
$$-y=-3$$ or 
$$y=3$$

anonymous · Answer

oops maybe i am wrong sorry .  let me check

anonymous · Answer

i may be wrong.

anonymous · Answer

jimmy rep is right and i am wrong.  i will see why

anonymous · Answer

oh because i wrote -4y and it is -3y.  my mistake.  sorry