a) Find all fourth roots of 1 in polar form.
b) Express them in Cartesian form.
c) Show how they can be expressed as powers of one fixed fourth root of 1.
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OpenStudy (amistre64):
4th roots in polar form divide the unit circle into 4 equal parts.... so 90 degree seperations
OpenStudy (amistre64):
since the any root of 1 = 1; im assuming they want (1,1) (1,-1) (-1,-1) (-1,1) as answers
OpenStudy (anonymous):
isnt it x^4=1?
OpenStudy (amistre64):
I was thinking \(\sqrt[4]{x}\) at \(x=1\)
OpenStudy (anonymous):
but i guess it is x=1^(1/4)
this is what we call four forth root of 1
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OpenStudy (anonymous):
x=1,-1,i,-i
OpenStudy (amistre64):
90s or the 45s....
OpenStudy (amistre64):
if we go with the i stuff; its the 90s and thats prolly the better interpretatio
OpenStudy (anonymous):
yup
OpenStudy (anonymous):
but for 1 its 0
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OpenStudy (anonymous):
for -1, pi
OpenStudy (amistre64):
there is no pi in the cartesian; just your 1s and 0s for your intercepts
OpenStudy (amistre64):
(1,0)
(0,1)
(-1,0)
(0,-1)
OpenStudy (amistre64):
but what 'c' is asking for I dunno
OpenStudy (amistre64):
maybe \((1-0i)^{1/4}\) ?
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OpenStudy (amistre64):
or is it simply \(i^4\)
OpenStudy (anonymous):
i cant guess any idea
OpenStudy (anonymous):
i^4 seems better
OpenStudy (amistre64):
im thinking the first since that implies a complex plane and 4 roots
OpenStudy (anonymous):
but how (-1,0) and(0,-1)
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OpenStudy (amistre64):
\((1+0i)^4\) maybe? if forget if its ^4 or ^(1/4) that pops out 4 times
OpenStudy (amistre64):
\(sqrt{-6}\) has complex roots right?
OpenStudy (anonymous):
look...when we talk about the cube roots of 1 , how we express it?
x=1^1/3..no?
OpenStudy (amistre64):
i believe so
OpenStudy (anonymous):
n for forth root it is
x=1^1/4
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OpenStudy (anonymous):
\[x^4 = 1\]
OpenStudy (amistre64):
sqrt(-9) = 3i and we can find both those roots in the complex plane ... gonna have to dbl chk with the wolfram :)
OpenStudy (anonymous):
\[(x^2-1)(x^2+1)=0\]
OpenStudy (anonymous):
x=1,-1,i,-i
OpenStudy (anonymous):
for x=1
r=1 and theta =0
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OpenStudy (anonymous):
x=-1
r=1, theta =pi
-1=cospi
OpenStudy (anonymous):
4th roots of 1 are 1, -1, i, -1
OpenStudy (anonymous):
you know one answer is 1. divide unit circle (in complex plane) into 4 equal parts and you will see i, -1, -i
OpenStudy (anonymous):
did u get part c?
OpenStudy (anonymous):
what is part c?
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OpenStudy (anonymous):
read the post:P
OpenStudy (anonymous):
oh yes they are all powers of i
OpenStudy (anonymous):
i, i^2, i^3, i^4 finito
OpenStudy (anonymous):
no question says" Show how they can be expressed as powers of one fixed fourth root of 1."
OpenStudy (anonymous):
that fixed root is i.
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OpenStudy (anonymous):
you cannot express i as a power of 1. i assume they mean integral powers