Question

represent ln5 as a definite intergral of the reciporcal function y=1/t

Answer 1

\[\int\limits_{1}^{5} 1/t \]

Answer 2

how would i grapth that to show the area it represents

Answer 3

well you just need to graph 1/t
and the area where x goes from 1 to 5

Answer 4

how do i enter that in the calc

Answer 5

with a graphic one you can do it. but I never used one

Answer 6

do you know how 1/t looks like?

Answer 7

no :/

Answer 8

http://www.wolframalpha.com/input/?i=graph+1%2Fx

Answer 9

the area you need is the one under the graph from x=1 to x=5

Answer 10

so the first one?

Answer 11

practice makes perfect, if you do calculus you need to be able to draw basic graphs of functions

Answer 12

http://www.wolframalpha.com/input/?i=graph+1%2Fx+from+1+to+5

Answer 13

so that is the the area? lol do i need to shade anything

Answer 14

shade under the graph until the x axes

Answer 15

perfect thanks

Answer 16

what is the x-intercept of the tangent to y=e^x at x=45

Answer 17

hmm, the derivative of e^x is e^x
so the tangent at x=45 has slope of e^45
and the actual value is the same so then tangent line is y=e^45+e^45x
the x intercept means that y=0
so 0=e^45+e^45x
x=-1
that means that from x=45 you need to go back 1 to get the y intercept
solution: x=44

Answer 18

okay thats what i got. sweet

Answer 19

well done!!