inverse cosine of square root of 3 over 2?
cos-1(square root of 3/2)

Question

owlfred · Answer

Hoot! You just asked your first question! Hang tight while I find people to answer it for you. You can thank people who give you good answers by clicking the 'Good Answer' button on the right!

myininaya · Answer

cos(pi/6)=square of 3/2

anonymous · Answer

$$\text{ArcCos}\left[\frac{\sqrt{3}}{2}\right]=\frac{\pi }{6}$$ Am not sure the square root of what was.

myininaya · Answer

what was?

myininaya · Answer

oops i missed my word root above

anonymous · Answer

was the argument of the cosine (square root 3)/2 or square root (3/2)

myininaya · Answer

i assumed it to be over just the numerator

anonymous · Answer

Thanks for responding.

myininaya · Answer

lol everyone needs love

myininaya · Answer

rob look at the post before this? do you agree with my attachment?

myininaya · Answer

the post by galaxy

myininaya · Answer

or i mean thread

anonymous · Answer

not sure what thread you are referring to.  do you have the web address?

myininaya · Answer

ok you see all the questions right?
right underneath this thread by hanbru there is galaxy (if sinx=1/3 and secy=5/4, where x and y lie btw 0 and pi/2, blah blah

myininaya · Answer

http://openstudy.com/groups/mathematics#/groups/mathematics/updates/4ddf14c3c9a28b0b52ad63c2