if you draw a 5-card hand from a standard deck of playing cards, how many hands could contain exactly 4 cards from the same suit?
wait a little confused. does this mean what is the probability you get exactly 4 cards of the same suit?
watchmath do you understand this question?
perhaps the answer is \[\dbinom{13}{4}\times \dbinom{39}{1}\times 4\]?
i don't really know how to intemperate "if you draw a 5-card hand"..."how many hands"
that is what i'm trying to figure out!
well maybe it means how many possible hand have 4 of one suit and two of another. if so, lets start with clubs. you need 4 clubs and 1 non club. the number of ways to get 4 clubs is \[\dbinom{13}{4}\] and the number of ways you can choose one non-club is \[\dbinom{39}{1}\]
then we do the same for each other suit hence multiply by 4
yes.....
my theory is 4(13 C4* 39C1)
that is what i wrote so it looks good to me
4*13*11*5*39
Thank you very much !!
welcome
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