Question

How do i solve squareroot 2 sinx+1=0

Answer 1

is the 2sinx+1 all under the radical and then it's = to 0 ?

Answer 2

oh sorry just the 2 is under the radical

Answer 3

ok you can isolate the radical by moving everything to the other side. then raise both sides to the power of 2. But i am not sure what varible you are solving for

Answer 4

but if sin is the coeffeciant of x then you should be able to divide to get them brake them down but i am not sure of this

Answer 5

oh ok thank you anyway

Answer 6

\[\sqrt{2}\sin x =-1\]\[\sin x =-1/\sqrt{2}\]\[x =\sin^{-1} -1/\sqrt{2}\]\[x =\pi/4\]

Answer 7

I'm sorry\[x =5\pi/4\]

Answer 8

sqrt_2 . sin_x + 1 = 0
sin_x = -1/sqrt_2
x = -pi/4 or 5pi/4

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