given that kx +6y = 1 and 2x + 3y = 1, what should be the value of k so that there will be no solution?

Please answer clearly and explain the solution clearly and easy to understand. Thanks!
(guaranteed medal for a good answer)

Question

given that kx +6y = 1 and 2x + 3y = 1, what should be the value of k so that there will be no solution?

Please answer clearly and explain the solution clearly and easy to understand. Thanks!
(guaranteed medal for a good answer)

aroub · Answer

is this question about slope ?

anonymous · Answer

At first glance it would seem that k = 4

anonymous · Answer

Put this into the equation then try to solve simultaneously
4x + 6y = 1
2x + 3y = 1
multiply equation 2 by 2
4x + 6y = 1
4x + 6y = 2
Subtract equation 1 from equation 2
Gives an answer 0=1
So k = 4

anonymous · Answer

Does that make sense?

moongazer · Answer

where did you get 4?

anonymous · Answer

I wanted to equate the LHS of both equations

anonymous · Answer

...and I could see that 3y could easily become 6y by multiplication hence 2x can become 4x

anonymous · Answer

thats a correct solution gian  theres his medal moongazer?

anonymous · Answer

Thank you Jimmy!