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Mathematics 8 Online
OpenStudy (cherrilyn):

LEIBNIZ TEST!

OpenStudy (cherrilyn):

why can't it be applied to..... 1/2 - 1/3 + 1/2^2 - 1/3^2 + 1/2^3 - 1/3^3... what method can be used to show convergence?

OpenStudy (watchmath):

Is the absolute value sequence decreasing?

OpenStudy (cherrilyn):

ummmmmmm. . . maybe? lol

OpenStudy (nowhereman):

That sequence definitely looks like a zero-sequence to me, so the Leibniz-test can be applied. The series converges!

OpenStudy (anonymous):

yep

OpenStudy (cherrilyn):

um..it says it cannot be applied. and I have to explain why not.

OpenStudy (cherrilyn):

It probably seems convergent because I don't know how to use the division sign on here :/

OpenStudy (watchmath):

Between 1/2^n and 1/2^(n+1) you have 1/3^n. But now 1/2^n > 1/3^n < 1/2^(n+1) So the absolute value sequence is not decreasing, hence we can't apply the Leibniz's test!

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