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Mathematics 11 Online
OpenStudy (anonymous):

I have a doubt which needs to be urgently solved cause i got a test tommorow!!!!!!!!The question is in the replies cause i cannot write a diagram or attach a diagram here!!!!! Its physics i know its a wrong section to ask at but i have no choice!!!!!!!

OpenStudy (anonymous):

I want to know how can we find the vertical component of the force vector here for normal reaction using \[N _{a}\cos \Theta\] rather than\[N_{a}\sin \Theta\]

OpenStudy (watchmath):

It depends on where your \(\Theta\) is

OpenStudy (anonymous):

hang on i am scanning the diagram

OpenStudy (anonymous):

here is the diagram pls answer quickly!!!!!!!!!!

OpenStudy (anonymous):

this fairly easy

OpenStudy (anonymous):

so answer it pls!!!!!!!!!!!!!

OpenStudy (anonymous):

well , just consider the angle between theta1 and the vector mg

OpenStudy (anonymous):

so then!!!!!!!!!!

OpenStudy (anonymous):

this will be 90 - theta

OpenStudy (anonymous):

then do trig in that triangle

OpenStudy (anonymous):

fine!!! further ahead!!!!!!!

OpenStudy (anonymous):

yeh.. im answering it , its just a bit slow lol

OpenStudy (anonymous):

k sorry!!!!!!

OpenStudy (anonymous):

i need to know why is the vertical component of say Na NaCos Theta and not Na sin Theta

OpenStudy (anonymous):

yeh , its basically because sin(90-x) = cos(x)

OpenStudy (anonymous):

lol, thats wrong cos(90-x) = sin(x)

OpenStudy (anonymous):

but is that the triangle we can use to do this cause i don't think so!!!!!!! and now i am confused with the two comments u made

OpenStudy (anonymous):

can any1 make a quick video and attach it i know i am asking way too much but pls do if possible!!!!!!!!

OpenStudy (anonymous):

ill draw a picture on paint , hopefully it will help lol

OpenStudy (anonymous):

k hopefully!!!!!!!!!!!!

OpenStudy (anonymous):

OpenStudy (anonymous):

ill do another one

OpenStudy (anonymous):

OpenStudy (anonymous):

second picture is just redrawing the top triangle in the previous picture, and marking in what you know

OpenStudy (anonymous):

now in the second triganle you apply trig sin( 90-x) = Na / Fy

OpenStudy (anonymous):

but sin(90-x) = cos(x)

OpenStudy (anonymous):

so Fy = Na / cos(x)

OpenStudy (anonymous):

wait dont think thats right

OpenStudy (anonymous):

thanks for ur effort but cud u use a the line tool to make the diagram cause this is really strange i am not able to make sense

OpenStudy (anonymous):

to be honest I dont really know what you are asking , what is the actual question ?

OpenStudy (anonymous):

and if you look at it , the second triangle , the one that has two sides ( one being the y axis and the other being the plane along the track

OpenStudy (anonymous):

that is a right angled trangle , and the angle between the track and the y axis is just 90-theta

OpenStudy (anonymous):

then you re draw the triangle and apply basic trig ratios and simply sin(90-x) to cos(x)

OpenStudy (anonymous):

i am trying to relate it to the concept of vectors which we can represent on the x axis and the y axis!!!!!

OpenStudy (anonymous):

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