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Whats the anti derivative of (1/(x^4)) ?? Need Help
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x^-4 x^-3 ---- i think -3
+C
yep
\(\frac{-1}{3x^3}+C\) lol
it looks to work like a derivative rule....
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\[\int\limits_{}^{}x^{n}dx=x^{n+1}/(n+1)+C\] here n=-4
1/x^4 = -1/3x^3 ....close..
so you dont brink the x ^4 to the numerater?
it's in the denominator so to bring it to the numerator you switch the sign of the exponent
ya i know that , but how is the one negative?
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\[\frac{x^{-4+1}}{-4+1}\]
\[\frac{x^-{3}}{-3}\]
\[-\frac{1}{3x^3}\]
thank you
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