Question

solve limx4 (sqrt 8-x)-2/(sqrt 5-x)-1

Answer 1

can you please show me step by step
thanks

Answer 2

lim x-->4 F(x)=F(4)=sqr (8-4)-2/sqr(5-4)-1=0/0 indefinite form

Answer 3

so we can use Hopital's rule

Answer 4

http://en.wikipedia.org/wiki/L'H%C3%B4pital's_rule

Answer 5

lim x-->4 [(sqr8-x)-2]'/[(sqr5-x)-1]'

Answer 6

Do u know derivatives?

Answer 7

i got the denomiator 0 and the numerator zero as well

Answer 8

not yet im currently taking calc

Answer 9

yea u can use Hopital's rule when u get 0/0 or infinite/infinite

Answer 10

ok thanks

Answer 11

[(sqr8-x)-2]'=1/2sqr(8-x) and [(sqr5-x)-1]'=1/2sqr(5-x)

so we'll have 1/2sqr(8-x) 2sqr(5-x)
lim x-->4 -------------=lim x-->4------------=1/2
1/2sqr(5-x) 2sqr(8-x)

Answer 12

Got it?

Answer 13

yes!! now i understand completely thank you soooo much..Im gonna refer to this as much as i can remeber

Answer 14

Happy i helped :)