Question

True or False?? File attached! (Please show how you know if its true/false)

Answer 1

1st is true

Answer 2

i dont think the first is true amistre it should be 9/x^3

Answer 3

rsvitale i think youre right about number one

Answer 4

you might be right :) without () around it count it as seperate right..

Answer 5

66. false
67. true by distributive property. (-1/6)*(x^2+3x)
68. false you're only multiplying the top by 5 it should be 5x^2/6
69. false you need to divide the first term by 3y as well
70. false
71.false same reasoning as 70. I can explain these if you want.
72.true x^2-8x+16=(x-4)^2. then take the square root.
73.true ln(e^2)=2ln(e)
74.false e^(l+s)=(e^l)*(e^s)

Answer 6

wow lol ok lets start with 67...why did you multiply by -1/6?

Answer 7

70 and 71:

assume sqrt(x+y)=sqrt(x)+sqrt(y)

square both sides

x+y=x+2sqrt(x)*sqrt(y)+y

this is not true unless x,y, or both are 0

so the equality cannot be true

Answer 8

dividing by -6 is the same as multiplying by (-1/6)

Answer 9

dividing by anything is the same as multiplying by its inverse.

Answer 10

ok gotcha

Answer 11

inverse as in 1/something, not the technical definition of inverse

Answer 12

do the other ones make sense?

Answer 13

ok and well im still going down the list trying to see if i get it. are you sure 73 is true? b/isnt 2lne not the same thing as just 2 by itself?

Answer 14

2lne=2. the equality is ln(e^2)=2

ln(e^2)=2ln(e)=2. ln(e)=1

Answer 15

e to what power=e? e^1=e

Answer 16

oh ok for some reason i thought lne^2=1

Answer 17

no ln(e^2) means e to what power is e^2. so it is 2.

Answer 18

ok so if i said e^27 it would be 27 correct?

Answer 19

ln(e^27)=27 correct

Answer 20

ok and i dont get the last one

Answer 21

(e^l)^(s)=e^(l*s) not e^(l+s)

Answer 22

do you want me to explain why?

Answer 23

but i thought when you multiply exponents you add them like (x^5)(x^3)=x^8

Answer 24

yeah that is right. But you are multiplying e^l by itself s times.

(e^l)^s=(e^l)*(e^l)*(e^l)*....*(e^l) <---- s times

=e^(l+l+l+l....+l <---s times)= e^(l*s)

Answer 25

oohhh ok i get it!! well thanks so much for your help!!

Answer 26

you're welcome :)