Question

Write the equation of the line that passes through the point (6, -2) and has a slope of -2/3

Answer 1

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Answer 2

y = -(2/3)(x-6)-2

Answer 3

\[y = -\frac{2x}{3} -6\]

Answer 4

that aint right is it..

Answer 5

idk lol

Answer 6

-*-=+ i see it

Answer 7

\[y = -\frac{2}{3}x-10\] maybe

Answer 8

im gonna have to do this the long way...

Answer 9

y=−(2/3)X + 2

Answer 10

thanks

Answer 11

y = -(2/3)(x-6)-2

y = (-2/3)x+(-2/3)-6 -2

y = (-2/3)x+(12/3) -2

y = (-2/3)x+2 is right

Answer 12

....fraction keep laughing at me

Answer 13

you need to use the point slope formula for these problems:
\[(y-y _{1}) = m(x - x _{1})\]

Answer 14

i shoulda multied his butt with a 3 ....thatd a showed it

Answer 15

so this isnt the right answer

Answer 16

just use the formula, y-y1=m(x-x1)
(6, -2) and has a slope of -2/3

y+2=-2/3(x-6)
3(y+2)=-2(x-6)
3y+6=-2x+12
2x+3y=12-6
2x+3y=6

Answer 17

this is right.