tan theta = -4/3 then sin theta =?
tan theta = sin theta / cos theta
yes i found sin theta = -4/3 cos theta
yes !
do u want options
what?
a) -4/5 but not 4/5 b) -4/5 or 4/5 c) 4/5 but not -4/5 d) none of these
\[sin(\theta)=\pm\frac{4}{5}\]
option b if you have no further information
how pls elaborate
ok if you draw a right triangle and think of one angle as theta, then you can visualize tangent as "opposite over adjacent" label the opposite side 4, the adjacent side 3 and the hypotenuse will be 5 by pythagoras
CAN U TELL ME WITH THE HELP OF FORMULA
ok we have one adjacent side 3 and opposite side 4 yes? then pythagoras tells us \[a^2+b^2=c^2\] where the sides are a and b and c is the hypotenuse. \[3^2+4^2=9+16=25\] so the hypotenuse is 5
if you think of sine as opposite over hypotenuse then you know \[\sin(x)=\frac{4}{5}\] but you do not know what quadrant you are in so you do not know if sine is positive or negative
I UNDERSTOOD VERY VERY VERY THANKS TO U
BUT The ratio of the radii of two circles at the centers of which two arcs of the same length subtended a angles of 60 degree and 70 degree is
welcome
CAN U ANSWER ME THIS QUESTION ALSO The ratio of the radii of two circles at the centers of which two arcs of the same length subtended a angles of 60 degree and 70 degree is
actually no because i do not know what the question means
OK ANYWAY THANKS
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