Question

f(t)=1.8(1.452)^t t=0 correspond to year2004.
In what year will sales reach 20 billion?

Answer 1

you are trying to solve \[20=1.8(1.452)^t\] for t.
divide by 1.8
\[\frac{20}{1.8}=(1.452)^t\] take the log of both sides
\[\ln(\frac{20}{1.8})=\ln((1.452)^t)=t\ln(1.452)\]

Answer 2

solve for t:

\[t=\frac{\ln(\frac{20}{1.8})}{\ln(1.452)}\]

Answer 3

thats what i got, but the answer would be 6.5 so the year 2010,

Answer 4

i get 6.4 so 6.4 years after 2004 is 2010.4 of there abouts.

Answer 5

but the question before asked what are sales in 2010 and my answer was 16.9.....not 20. im confused

Answer 6

maybe be safe and say by 2011

Answer 7

i guess the additional .5 counts! let me try it.

Answer 8

thanks so much

Answer 9

welcome!