Here is a good one. :)
A manufacturer is designing special packaging for a product in the shape of a truncated pyramid. A truncated pyramid is a pyramid with the top cut off. The model he is building is included. The bases are not regular figures. The lateral sides are trapezoids. The height of each trapezoid face is 12 cm. Determine the amount of material needed to build the model (assume no overlap on the sides).

Question

Here is a good one. :)
A manufacturer is designing special packaging for a product in the shape of a truncated pyramid. A truncated pyramid is a pyramid with the top cut off. The model  he is building is included. The bases are not regular figures. The lateral sides are trapezoids. The height of each trapezoid face is 12 cm. Determine the amount of material needed to build the model (assume no overlap on the sides).

anonymous · Answer

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mathteacher1729 · Answer

Find the area of the big pyramid, and subtract from that the area of the little pyramid.  Be careful to ADD BACK the base of the small pyramid since it will be the top of the package.  Hope this helps.

anonymous · Answer

thank you I will give it a shot! :)

dumbcow · Answer

normally i would agree but in this case you dont know the height of the triangular faces, only the height of the trapezoids
use area of trapezoid formula (1/2*h(b1+b2)) to find area of all 3 trapezoid faces then add the 2 right triangle areas (top and bottom)
i get 246

anonymous · Answer

yes I have the formula for the trapezoid

anonymous · Answer

Ill check mine

amistre64 · Answer

6(3+6) + 6(4+8) + 6(5+10) +2(3) + 4(6) = Sa  from my point of view

amistre64 · Answer

54 + 72 + 90 + 6 +24

120 + 126 = 246

anonymous · Answer

i just got that... yes it matches both :)

anonymous · Answer

and that is how much material is needed .....
246 cm^2