Question

Can someone explain how to solve \[3^{-1/3}\times27^{-1/2}\] Thanks! :)

Answer 1

\[3^{-1/3}\times3^{3(-1/2)}\]
\[3^{-1/3+(-3/2)}\]
\[3^{-1/3-3/2}\]
\[3^{(-2-9)/6}\]
\[3^{-11/6}\]

Answer 2

how do you simplify that further? :D

Answer 3

\[27=3^{3}\]
then solve the fraction...

Answer 4

\[a ^{m} \times a ^{n}=a ^{m+n}\]
the base must equal...

Answer 5

i mean, how do you simplify \[3^{-11/6}\] further? because actually, i got that answer too. but the answer isn't in the choices given. thanks!

Answer 6

what the choices?

Answer 7

\[\sqrt[6]{3}\] \[\sqrt[6]{3}/9\] \[3\sqrt[6]{3}/2\] and \[3\sqrt[6]{3}\]

Answer 8

\[3^{-\frac{11}{6}} =3^{-2}.3^{1/6}={\sqrt[6]{3} \over 9}\]

Answer 9

the answer is \[\sqrt[6]{3}/9\]
\[3^{-11/6}=\]
\[\sqrt[6]{3^{-11}}\]
\[\sqrt[6]{3^{1}/3^{12}}\]
\[\sqrt[6]{3^{1}}/\sqrt[6]{12}\]
\[\sqrt[6]{3}/3^{12(1/6)}\]
\[\sqrt[6]{3}/3^{2}\]
\[\sqrt[6]{3}/9\]

Answer 10

Anwara, how is 3−116=3−2.31/6 ?

Answer 11

wow,anwar.how do u do that?

Answer 12

i meant, how did you get to the 2nd equation? and thanks, mohsen!

Answer 13

Because \(-2+1/6= \frac{-12+1}{6}=-11/6\), which is the same exponent :)

Answer 14

@Mohsen: do what?

Answer 15

same question with phoebeca :)
bt u answered it :)
thanks

Answer 16

You're welcome!

Answer 17

thanks guys!

Answer 18

i'm a teacher but still impress your answer,anwar :)

Answer 19

i agree!

Answer 20

Thanks mohsen :)