How do I find the twelfth term of 5,8,11,14

Question

anonymous · Answer

That's an arithmetic progression. The formula for the nth term of an arithmetic progression is:$$u _{n}=a+(n-1)d$$Where a is the first term and d is common difference. So, to find the twelfth term of this sequence:$$u _{12}=a+(12-1)d=5+11\times3=38$$

amistre64 · Answer

its adding 3

amistre64 · Answer

A{n} = A{n-1} +3

anonymous · Answer

That's the recurrence relation but that's not particularly necessary here.

amistre64 · Answer

i dont operate on necessary lol

anonymous · Answer

Ok thank you

anonymous · Answer

its 3n + 2 :D( n = term) 
for n = 1(first term):
3 + 2 =5
for n= 2(second term): 
6 + 2 = 8
for n=20(20th term)
60 + 2 = 62 
kk?

anonymous · Answer

just they way i solve is really easier

amistre64 · Answer

$A_n = A_{n-1}+3$; and $A_{n-1} = A_{n-2}+3$

$$A_n = A_{n-2}+3+3 \iff A_n=A_{n-2}+2(3)$$
$$A_n = A_{n-r} + r(3)$$
$A_{n-r} = A_1;$ when $r = n-1$

$A_n = A_1 + (n-1)(3);$ and $A_1 = 5$
$$A_{12} = 5 + (12-1)(3) = 38$$
Thats how you learn it in discrete math ...

anonymous · Answer

97 to go and then i open a bottle of champagne!

amistre64 · Answer

97..years? or seonds lol

anonymous · Answer

if it happens when i am not here i will be sad

amistre64 · Answer

ill send a carrier pigeon just before it happens to let you know lol