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find the vertical asymptotes of the function givem (x^2+7)/(9x-5x^2) please provide the smallest value and the largest value of x.
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can you please show me step by step
set the denominator = 0 and solve:
\[9x-5x^2=0\] \[x(9-5x)=0\] \[x=0\] or \[x=\frac{9}{5}\]
those are your vertical asymptotes
horizontal one is \[y=-\frac{1}{5}\] since the degree of numerator and denominator are the same it is the ratio of the leading coefficients. not that you asked
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ok cool thank you veyr much
welcome
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