Question

factor 12v^2+36vp+27p^2

Answer 1

3(4v^2+12vp+9p^2)

Answer 2

can it be factored further?

Answer 3

Yes. Note that there is a perfect square hidden in \[3(4v^2+12vp+9p^2)\]

\[3(4v^2+12vp+9p^2)=3(2v+3p)(2v+3p)\]

So that means

\[
12v^2+36vp+27p^2
=3(4v^2+12vp+9p^2)
=2(2v+3p)^2
\]

Answer 4

3(2v+3p)^2??

Answer 5

To see if that is the answer, expand it. First compute \[(2v+3p)^2\] and then multiply that by three. :)