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Mathematics 13 Online
OpenStudy (anonymous):

A chemical-storage tank is a cylinder with a hemisphere cap on each end. If the height of the cylindrical portion is 16.2 ft and the radius of the cylinder and hemispheres is 2.8 ft, how many cubic feet of a chemical will the tank hold.

OpenStudy (anonymous):

OpenStudy (mathteacher1729):

I think for your class you might want to print out this little cheat sheet: http://math2.org/math/geometry/areasvols.htm :)

OpenStudy (anonymous):

Neat... thanks... its just starting the problem sometimes

OpenStudy (mathteacher1729):

"Always look for the question mark." That sentence usually tells you what you're looking for. Is it area, is it volume, etc? Once you know that, then you can use the appropriate formulas to find ...area or volume, etc.

OpenStudy (anonymous):

Volume... ?? but im not sure what to subtract with the top on it

OpenStudy (anonymous):

volume is to fill right?

OpenStudy (amistre64):

Vcyl + Vhemi = Vtotal but your pic has a cone and not a halfsphere?

OpenStudy (amistre64):

in fact your q and your pic dont match at all lol

OpenStudy (radar):

I would solved for the cylinder volume first. Since you will have the hemishphere on each end, calculate for the a sphere of the given radius. I got 399 cubic feet for the cylinder portion, and 91.595232 cubic feet for the ends giving a total cubic feet of 490.95

OpenStudy (anonymous):

ha ignore the picture... that went to a different problem... how embarrassing... good catch!!

OpenStudy (anonymous):

Danger... thats good math skills right there Amistre.. LOL

OpenStudy (amistre64):

Vcyl = (16.2) pi (2.8)^2 Vsph = (4/3) pi (2.8)^3

OpenStudy (anonymous):

yes

OpenStudy (amistre64):

490.960....

OpenStudy (anonymous):

kk... I have to do it the slow way... I'll check ...

OpenStudy (amistre64):

:) thats fine

OpenStudy (anonymous):

yes I got by adding the two answers 490.95971 is that the cubic feet that will fill the tank... or more steps involved... LOL

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