Question

(w-6/w-8)-(w+1/w+8)+(w-40/w^2-64)=?????????

Answer 1

Are you being asked to simplify the following?

\[\frac{w-6}{w-8}+\frac{w+1}{w+8}+\frac{w-40}{w^2-64}\]

Answer 2

yes

Answer 3

no

Answer 4

the 1 st is minus

Answer 5

(w-6/w-8)-(w+1/w+8)+(w-40/w^2-64)

Answer 6

\[\frac{w-6}{w-8}-\frac{w+1}{w+8}+\frac{w-40}{w^2-64}\]

Answer 7

Since you're being asked to simplify, you want all three fractions to have a common denominator. Luckily \[w^2-64 =(w+8)(w-8)\] so that means we can leave that term alone and multiply the others like this:
\[\frac{w-6}{w-8}\cdot\frac{w+8}{w+8}-\frac{w+1}{w+8}\cdot\frac{w-8}{w-8}+\frac{w-40}{w^2-64}\]

That LOOKS like a gigantic mess... But it gets better. We now have a common denominator...

\[\frac{(w-6)(w-8) - (w+1)(w-8) + (w-40)}{w^2-64}\]

And THAT just requires us to distribute and collect terms. :)

Hope this helps!