Question

((2+i)/(3-i))+((2-i)/(4i))
explanation please

Answer 1

do u know that these are complex numbers eg 2 + i

Answer 2

yes

Answer 3

u need to rationalise the denominators by multiplying them by their complements

the complement of 3-i is 3+i (changed sign)


so we have
(2+i)((3+i)/(3-i)(3+i) + (2-i)4i / 4i(4i)

(6+2i+3i -1)/ 9+1 + 8i +4/-16
(5 +5i )/ 10 - (8i+4)16

Answer 4

what do i do after that?

Answer 5

i suppose we should write it as one fraction

(1+i) / 2 - (2i+1) / 4

= (2+2i )/ 4 - (2i+1) / 4

= 1/4

Answer 6

do i need a common denominator?

Answer 7

wow - that neat- if i'm right of couse

Answer 8

you are i checked it on my calculator but i didnt know how to get it.... and i factor right?

Answer 9

sorry i dont know exactly what you mean (i'm a brit see!!)

Answer 10

nevermind but thanks

Answer 11

i understand it now

Answer 12

good