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whats the derivative of (lnt)^2
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use chain rule =2*ln(t)*1/t
srry my question was actually the integral of this problem
lol srry i was asking for the derivative
thank you for your help
oh ok use integration by parts then u=ln(t) dv=ln(t) du= 1/t v = tlnt - t
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can i just say that my u is (lnt)^2 and that my dv is 1
yeah i guess that will work too
k ty
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