Factor completely
9x^6-54x^5+18x^4
the complete factorization is????

Question

Factor completely 
9x^6-54x^5+18x^4
the complete factorization is????

amistre64 · Answer

take out commons; x^4 seems the most commmon

amistre64 · Answer

9 also goes into it all

amistre64 · Answer

9x^4 (x^2 -6x +2)

amistre64 · Answer

the rest might me tricky in that i think we get sqrts involved

amistre64 · Answer

3 +- sqrt(28)/2  ad that aint gona be pretty

amistre64 · Answer

3 +- sqrt(7)

its either what I first did or it will ome to this:

9x^4(x -(3-sqrt(7)))(x-(3+sqrt(7)))  if I kept track of it

anonymous · Answer

9x^4 (x^2 -6x +2) this is your first answer right?

anonymous · Answer

you have a few things going on so wasnt sure if that was the answer

anonymous · Answer

You are correct (except you left out x=0 as one of the solutions.
the remaining x^2-6x+2 factors out to 3 + sqrt(7) and 3-sqrt(7)
Use the pythagorean theorem to get the above answers.
ax^2+bx+c=0 so a=1, b=-6, and c = 2; just plug those into the theorem to get 3 + sqrt(7) and 3-sqrt(7)