5/4x+1/8x=5/8+x ?? I am so bad at fractions
like this?: \[\frac{5}{4}x+\frac{1}{8}x=\frac{5}{8}+x\]
yes but how do you solve it??
ok, multiply everything by 8: 10x+x=5+8x 3x=5 x=5/3
ok
why do we multiply itby 8 b/c it is the common denominator?
its the least common multiple of the denominators, so it gets rid of all the fractions.
ok I will kepp that in mind thank you..
you're welcome
do you k now anything about the elimination method?
do you have a specific problem?
just getting it to opposite and yes! the 5x+6y=2 10x+12y=4
well those equations are multiples of each other
so elimination isnt really useful here
that answer calls for use of the elimination
to eliminate either x or y you multiply the first equation by -2, then add. But then you get 0=0
there are actually many solutions to that system
theyre both the same equation
there is an option for no solutions or many solutions
so many solutions woiuld fit
there are many solutions, because theyre both the same equation so you can pick any x and find a corresponding y to make the equation true
thank you again
but something like 2x+3y=15 4x+y=20 you would multiply the first equation by -2 and then add them together to eliminate x -4x-6y=-30 4x+y=20 -5y=-10 y=2 then plug back in to find x 2x+6=15 x=9/2
then the solution is unique
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